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![SOLVED: P(A + BIC) = 1 P(ABIC) = 1 P(AIc)p(BIAC) ≠- P(AIC)[1 P(BIAc)] = P(AIC) + P(ABIC) (2.65) P(AIC) + P(BIC)p(AIBC) = P(AIC) + P(BICH[I = P(AIBC)] and finally P(A +](https://cdn.numerade.com/ask_images/ed480480e3ec42718bd86fa4a117060f.jpg "SOLVED: P(A + BIC) = 1 P(ABIC) = 1 P(AIc)p(BIAC) ≠- P(AIC)[1 P(BIAc)] = P(AIC) + P(ABIC) (2.65) P(AIC) + P(BIC)p(AIBC) = P(AIC) + P(BICH[I = P(AIBC)] and finally P(A +")
SOLVED: P(A + BIC) = 1 P(ABIC) = 1 P(AIc)p(BIAC) ≠- P(AIC)[1 P(BIAc)] = P(AIC) + P(ABIC) (2.65) P(AIC) + P(BIC)p(AIBC) = P(AIC) + P(BICH[I = P(AIBC)] and finally P(A +
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